j*sin(2*z)=3*cos(2*z)+2

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Solution for j*sin(2*z)=3*cos(2*z)+2 equation:


Simplifying
j * sin(2z) = 3cos(2z) + 2

Remove parenthesis around (2z)
j * ins * 2z = 3cos(2z) + 2

Reorder the terms for easier multiplication:
2j * ins * z = 3cos(2z) + 2

Multiply j * ins
2ijns * z = 3cos(2z) + 2

Multiply ijns * z
2ijnsz = 3cos(2z) + 2

Remove parenthesis around (2z)
2ijnsz = 3cos * 2z + 2

Reorder the terms for easier multiplication:
2ijnsz = 3 * 2cos * z + 2

Multiply 3 * 2
2ijnsz = 6cos * z + 2

Multiply cos * z
2ijnsz = 6cosz + 2

Reorder the terms:
2ijnsz = 2 + 6cosz

Solving
2ijnsz = 2 + 6cosz

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Divide each side by '2jnsz'.
i = j-1n-1s-1z-1 + 3cj-1n-1o

Simplifying
i = j-1n-1s-1z-1 + 3cj-1n-1o

Reorder the terms:
i = 3cj-1n-1o + j-1n-1s-1z-1

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