i+(3-5i)-2(2-3i)=0

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Solution for i+(3-5i)-2(2-3i)=0 equation:


Simplifying
i + (3 + -5i) + -2(2 + -3i) = 0

Remove parenthesis around (3 + -5i)
i + 3 + -5i + -2(2 + -3i) = 0
i + 3 + -5i + (2 * -2 + -3i * -2) = 0
i + 3 + -5i + (-4 + 6i) = 0

Reorder the terms:
3 + -4 + i + -5i + 6i = 0

Combine like terms: 3 + -4 = -1
-1 + i + -5i + 6i = 0

Combine like terms: i + -5i = -4i
-1 + -4i + 6i = 0

Combine like terms: -4i + 6i = 2i
-1 + 2i = 0

Solving
-1 + 2i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 2i = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 2i = 0 + 1
2i = 0 + 1

Combine like terms: 0 + 1 = 1
2i = 1

Divide each side by '2'.
i = 0.5

Simplifying
i = 0.5

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