h2-238h+(1565/2)=0

Solution for h2-238h+(1565/2)=0 equation:

h2-238h+(1565/2)=0

We add all the numbers together, and all the variables

h2-238h+(+1565/2)=0

We add all the numbers together, and all the variables

h^2-238h+(+1565/2)=0

We get rid of parentheses

h^2-238h+1565/2=0

We multiply all the terms by the denominator


h^2*2-238h*2+1565=0

Wy multiply elements

2h^2-476h+1565=0

a = 2; b = -476; c = +1565;
Δ = b2-4ac
Δ = -4762-4·2·1565
Δ = 214056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{214056}=\sqrt{36*5946}=\sqrt{36}*\sqrt{5946}=6\sqrt{5946}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-476)-6\sqrt{5946}}{2*2}=\frac{476-6\sqrt{5946}}{4}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-476)+6\sqrt{5946}}{2*2}=\frac{476+6\sqrt{5946}}{4}
$