h/2-h/h-4=-4/h-4

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Solution for h/2-h/h-4=-4/h-4 equation: 


D( h )

h = 0

h = 0

h = 0

h in (-oo:0) U (0:+oo)

h/2-(h/h)-4 = -4/h-4 // + -4/h-4

h/2-(-4/h)-(h/h)-4+4 = 0

h/2+4*h^-1-4-1+4 = 0

1/2*h^1+4*h^-1-1*h^0 = 0

(1/2*h^2-1*h^1+4*h^0)/(h^1) = 0 // * h^2

h^1*(1/2*h^2-1*h^1+4*h^0) = 0

h^1

(1/2)*h^2-h+4 = 0

(1/2)*h^2-h+4 = 0

DELTA = (-1)^2-(4*4*(1/2))

DELTA = -7

DELTA < 0

h in { } 

h belongs to the empty set

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