h+1+2(h+1)=3(h+2)=3(h+2)-h+2

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Solution for h+1+2(h+1)=3(h+2)=3(h+2)-h+2 equation: 



h+1+2(h+1)=3(h+2)=3(h+2)-h+2

We move all terms to the left:

h+1+2(h+1)-(3(h+2))=0

We multiply parentheses

h+2h-(3(h+2))+2+1=0



We calculate terms in parentheses: -(3(h+2)), so:

3(h+2)

We multiply parentheses

3h+6

Back to the equation:

-(3h+6)



We add all the numbers together, and all the variables

3h-(3h+6)+3=0

We get rid of parentheses

3h-3h-6+3=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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