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h(h+5)=26.24
We move all terms to the left:
h(h+5)-(26.24)=0
We add all the numbers together, and all the variables
h(h+5)-26.24=0
We multiply parentheses
h^2+5h-26.24=0
a = 1; b = 5; c = -26.24;
Δ = b2-4ac
Δ = 52-4·1·(-26.24)
Δ = 129.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{129.96}}{2*1}=\frac{-5-\sqrt{129.96}}{2} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{129.96}}{2*1}=\frac{-5+\sqrt{129.96}}{2} $
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