g(2)=4,000(6)0.3(2)

Solution for g(2)=4,000(6)0.3(2) equation:

g(2)=4.000(6)0.3(2)

We move all terms to the left:

g(2)-(4.000(6)0.3(2))=0

We add all the numbers together, and all the variables

g2-(1.280192)=0

We add all the numbers together, and all the variables

g^2-1.280192=0

a = 1; b = 0; c = -1.280192;
Δ = b2-4ac
Δ = 02-4·1·(-1.280192)
Δ = 5.120768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{5.120768}}{2*1}=\frac{0-\sqrt{5.120768}}{2}
=-\frac{\sqrt{}}{2}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{5.120768}}{2*1}=\frac{0+\sqrt{5.120768}}{2}
=\frac{\sqrt{}}{2}
$