f=kq1q2/d2

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Solution for f=kq1q2/d2 equation: 


(3/5)*x-((2/3)*x) = 0

(1/3)*x^23.09 = 0

k/2-513 = 0

5.4/2.1 = 0

(5*x)/(3*x-5) = 9

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