f=(r-z)/n

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Solution for f=(r-z)/n equation: 


x in (-oo:+oo)

f = (r-z)/n // - (r-z)/n

f-((r-z)/n) = 0

(-1*(r-z))/n+f = 0

(-1*(r-z))/n+(f*n)/n = 0

f*n-1*(r-z) = 0

f*n-r+z = 0

(f*n-r+z)/n = 0

(f*n-r+z)/n = 0 // * n

f*n-r+z = 0

x belongs to the empty set

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