f+2f+6=3(f+2)

Solution for f+2f+6=3(f+2) equation:

Simplifying
f + 2f + 6 = 3(f + 2)

Reorder the terms:
6 + f + 2f = 3(f + 2)

Combine like terms: f + 2f = 3f
6 + 3f = 3(f + 2)

Reorder the terms:
6 + 3f = 3(2 + f)
6 + 3f = (2 * 3 + f * 3)
6 + 3f = (6 + 3f)

Add '-6' to each side of the equation.
6 + -6 + 3f = 6 + -6 + 3f

Combine like terms: 6 + -6 = 0
0 + 3f = 6 + -6 + 3f
3f = 6 + -6 + 3f

Combine like terms: 6 + -6 = 0
3f = 0 + 3f
3f = 3f

Add '-3f' to each side of the equation.
3f + -3f = 3f + -3f

Combine like terms: 3f + -3f = 0
0 = 3f + -3f

Combine like terms: 3f + -3f = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.