f(x)=3/2x-9

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Solution for f(x)=3/2x-9 equation: 


(16*q^0*r^6)/(4*q^-3) = 0

(5/2)*x = (8/3)*x-6

60 = (2.4*(x+1))/(0.15-x)

(3*y)/2-((14*y-3)/5) = (y-4)/4

(3*y)/2-(14*y)-(3/5) = y-(4/4)

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