f(n+1)=f(n)-5

Solution for f(n+1)=f(n)-5 equation:

Simplifying
f(n + 1) = f(n) + -5

Reorder the terms:
f(1 + n) = f(n) + -5
(1 * f + n * f) = f(n) + -5
(1f + fn) = f(n) + -5

Multiply f * n
1f + fn = fn + -5

Reorder the terms:
1f + fn = -5 + fn

Add '-1fn' to each side of the equation.
1f + fn + -1fn = -5 + fn + -1fn

Combine like terms: fn + -1fn = 0
1f + 0 = -5 + fn + -1fn
1f = -5 + fn + -1fn

Combine like terms: fn + -1fn = 0
1f = -5 + 0
1f = -5

Solving
1f = -5

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by '1'.
f = -5

Simplifying
f = -5