f(n+1)=-2f(n)+8

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Solution for f(n+1)=-2f(n)+8 equation:


Simplifying
f(n + 1) = -2f(n) + 8

Reorder the terms:
f(1 + n) = -2f(n) + 8
(1 * f + n * f) = -2f(n) + 8
(1f + fn) = -2f(n) + 8

Multiply f * n
1f + fn = -2fn + 8

Reorder the terms:
1f + fn = 8 + -2fn

Solving
1f + fn = 8 + -2fn

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '2fn' to each side of the equation.
1f + fn + 2fn = 8 + -2fn + 2fn

Combine like terms: fn + 2fn = 3fn
1f + 3fn = 8 + -2fn + 2fn

Combine like terms: -2fn + 2fn = 0
1f + 3fn = 8 + 0
1f + 3fn = 8

Reorder the terms:
-8 + 1f + 3fn = 8 + -8

Combine like terms: 8 + -8 = 0
-8 + 1f + 3fn = 0

The solution to this equation could not be determined.

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