f(n)=2f(n-1)+1

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Solution for f(n)=2f(n-1)+1 equation:


Simplifying
f(n) = 2f(n + -1) + 1

Multiply f * n
fn = 2f(n + -1) + 1

Reorder the terms:
fn = 2f(-1 + n) + 1
fn = (-1 * 2f + n * 2f) + 1
fn = (-2f + 2fn) + 1

Reorder the terms:
fn = 1 + -2f + 2fn

Solving
fn = 1 + -2f + 2fn

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '2f' to each side of the equation.
2f + fn = 1 + -2f + 2f + 2fn

Combine like terms: -2f + 2f = 0
2f + fn = 1 + 0 + 2fn
2f + fn = 1 + 2fn

Add '-2fn' to each side of the equation.
2f + fn + -2fn = 1 + 2fn + -2fn

Combine like terms: fn + -2fn = -1fn
2f + -1fn = 1 + 2fn + -2fn

Combine like terms: 2fn + -2fn = 0
2f + -1fn = 1 + 0
2f + -1fn = 1

Reorder the terms:
-1 + 2f + -1fn = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + 2f + -1fn = 0

The solution to this equation could not be determined.

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