f(g(x))=1-(2x+1)squared

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Solution for f(g(x))=1-(2x+1)squared equation:


Simplifying
f(g(x)) = 1 + -1(2x + 1) * squared

Multiply g * x
f(gx) = 1 + -1(2x + 1) * squared

Multiply f * gx
fgx = 1 + -1(2x + 1) * squared

Reorder the terms:
fgx = 1 + -1(1 + 2x) * squared

Reorder the terms for easier multiplication:
fgx = 1 + -1adeqrsu(1 + 2x)
fgx = 1 + (1 * -1adeqrsu + 2x * -1adeqrsu)
fgx = 1 + (-1adeqrsu + -2adeqrsux)

Solving
fgx = 1 + -1adeqrsu + -2adeqrsux

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'gx'.
f = g-1x-1 + -1adeg-1qrsux-1 + -2adeg-1qrsu

Simplifying
f = g-1x-1 + -1adeg-1qrsux-1 + -2adeg-1qrsu

Reorder the terms:
f = -2adeg-1qrsu + -1adeg-1qrsux-1 + g-1x-1

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