f(2n+1)=5-3(2n+1)

Solution for f(2n+1)=5-3(2n+1) equation:

Simplifying
f(2n + 1) = 5 + -3(2n + 1)

Reorder the terms:
f(1 + 2n) = 5 + -3(2n + 1)
(1 * f + 2n * f) = 5 + -3(2n + 1)
(1f + 2fn) = 5 + -3(2n + 1)

Reorder the terms:
1f + 2fn = 5 + -3(1 + 2n)
1f + 2fn = 5 + (1 * -3 + 2n * -3)
1f + 2fn = 5 + (-3 + -6n)

Combine like terms: 5 + -3 = 2
1f + 2fn = 2 + -6n

Solving
1f + 2fn = 2 + -6n

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
-2 + 1f + 2fn + 6n = 2 + -6n + -2 + 6n

Reorder the terms:
-2 + 1f + 2fn + 6n = 2 + -2 + -6n + 6n

Combine like terms: 2 + -2 = 0
-2 + 1f + 2fn + 6n = 0 + -6n + 6n
-2 + 1f + 2fn + 6n = -6n + 6n

Combine like terms: -6n + 6n = 0
-2 + 1f + 2fn + 6n = 0

The solution to this equation could not be determined.