Below you can find the full step by step solution for you problem. We hope it will be very helpful for you and it will help you to understand the solving process.
(sin(2*x)-cos(4*x))'The calculation above is a derivative of the function f (x)
(sin(2*x))'+(-cos(4*x))'
cos(2*x)*(2*x)'+(-cos(4*x))'
cos(2*x)*((2)'*x+2*(x)')+(-cos(4*x))'
cos(2*x)*(0*x+2*(x)')+(-cos(4*x))'
cos(2*x)*(0*x+2*1)+(-cos(4*x))'
2*cos(2*x)+(-cos(4*x))'
2*cos(2*x)-sin(4*x)*(4*x)'
2*cos(2*x)-sin(4*x)*((4)'*x+4*(x)')
2*cos(2*x)-sin(4*x)*(0*x+4*(x)')
2*cos(2*x)-sin(4*x)*(0*x+4*1)
2*cos(2*x)+4*(-sin(4*x))
2*cos(2*x)+4*sin(4*x)
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