Derivative of 3sin(2x)cos(2x)

Derivative of 3sin(2x)cos(2x). Simple step by step solution, to learn. Simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Derivative of 3sin(2x)cos(2x): 


(3*sin(2*x)*cos(2*x))'

(3*sin(2*x))'*cos(2*x)+3*sin(2*x)*(cos(2*x))'

((3)'*sin(2*x)+3*(sin(2*x))')*cos(2*x)+3*sin(2*x)*(cos(2*x))'

(0*sin(2*x)+3*(sin(2*x))')*cos(2*x)+3*sin(2*x)*(cos(2*x))'

(0*sin(2*x)+3*cos(2*x)*(2*x)')*cos(2*x)+3*sin(2*x)*(cos(2*x))'

(0*sin(2*x)+3*cos(2*x)*((2)'*x+2*(x)'))*cos(2*x)+3*sin(2*x)*(cos(2*x))'

(0*sin(2*x)+3*cos(2*x)*(0*x+2*(x)'))*cos(2*x)+3*sin(2*x)*(cos(2*x))'

(0*sin(2*x)+3*cos(2*x)*(0*x+2*1))*cos(2*x)+3*sin(2*x)*(cos(2*x))'

(0*sin(2*x)+3*2*cos(2*x))*cos(2*x)+3*sin(2*x)*(cos(2*x))'

6*cos(2*x)*cos(2*x)+3*sin(2*x)*(cos(2*x))'

6*cos(2*x)*cos(2*x)+3*sin(2*x)*-sin(2*x)*(2*x)'

6*cos(2*x)*cos(2*x)+3*sin(2*x)*-sin(2*x)*((2)'*x+2*(x)')

6*cos(2*x)*cos(2*x)+3*sin(2*x)*-sin(2*x)*(0*x+2*(x)')

6*cos(2*x)*cos(2*x)+3*sin(2*x)*-sin(2*x)*(0*x+2*1)

6*cos(2*x)*cos(2*x)+3*sin(2*x)*2*(-sin(2*x))

6*cos(2*x)*cos(2*x)+3*sin(2*x)*-2*sin(2*x)

6*(cos(2*x))^2-(6*(sin(2*x))^2)

The calculation above is a derivative of the function f (x)

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