Derivative of 2sin(x)-3cos(2x)

Derivative of 2sin(x)-3cos(2x). Simple step by step solution, to learn. Simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Derivative of 2sin(x)-3cos(2x): 


(2*sin(x)-(3*cos(2*x)))'

(2*sin(x))'+(-(3*cos(2*x)))'

(2)'*sin(x)+2*(sin(x))'+(-(3*cos(2*x)))'

0*sin(x)+2*(sin(x))'+(-(3*cos(2*x)))'

0*sin(x)+2*cos(x)+(-(3*cos(2*x)))'

2*cos(x)+(3)'*cos(2*x)+3*(cos(2*x))'

2*cos(x)+0*cos(2*x)+3*(cos(2*x))'

2*cos(x)+0*cos(2*x)+3*-sin(2*x)*(2*x)'

2*cos(x)+0*cos(2*x)+3*-sin(2*x)*((2)'*x+2*(x)')

2*cos(x)+0*cos(2*x)+3*-sin(2*x)*(0*x+2*(x)')

2*cos(x)+0*cos(2*x)+3*-sin(2*x)*(0*x+2*1)

2*cos(x)+0*cos(2*x)+3*2*(-sin(2*x))

2*cos(x)+0*cos(2*x)+3*-2*sin(2*x)

2*cos(x)+6*sin(2*x)

The calculation above is a derivative of the function f (x)

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