Derivative of 0.2*sin(2*pi*40*x)

Derivative of 0.2*sin(2*pi*40*x). Simple step by step solution, to learn. Simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Derivative of 0.2*sin(2*pi*40*x): 


(0.2*sin(2*40*pi*x))'

(0.2)'*sin(2*40*pi*x)+0.2*(sin(2*40*pi*x))'

0*sin(2*40*pi*x)+0.2*(sin(2*40*pi*x))'

0*sin(2*40*pi*x)+0.2*cos(2*40*pi*x)*(2*40*pi*x)'

0*sin(2*40*pi*x)+0.2*cos(2*40*pi*x)*((2*40*pi)'*x+2*40*pi*(x)')

0*sin(2*40*pi*x)+0.2*cos(2*40*pi*x)*(0*x+2*40*pi*(x)')

0*sin(2*40*pi*x)+0.2*cos(2*40*pi*x)*(0*x+2*40*pi*1)

0*sin(2*40*pi*x)+0.2*80*pi*cos(2*40*pi*x)

0*sin(2*40*pi*x)+0.2*80*pi*cos(80*pi*x)

16*pi*cos(80*pi*x)

The calculation above is a derivative of the function f (x)

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