Below you can find the full step by step solution for you problem. We hope it will be very helpful for you and it will help you to understand the solving process.
(((sin(10*x))^3)/2)'The calculation above is a derivative of the function f (x)
(((sin(10*x))^3)'*2-((sin(10*x))^3*(2)'))/(2^2)
(3*(sin(10*x))^(3-1)*(sin(10*x))'*2-((sin(10*x))^3*(2)'))/(2^2)
(3*(sin(10*x))^(3-1)*cos(10*x)*(10*x)'*2-((sin(10*x))^3*(2)'))/(2^2)
(3*(sin(10*x))^(3-1)*cos(10*x)*((10)'*x+10*(x)')*2-((sin(10*x))^3*(2)'))/(2^2)
(3*(sin(10*x))^(3-1)*cos(10*x)*(0*x+10*(x)')*2-((sin(10*x))^3*(2)'))/(2^2)
(3*(sin(10*x))^(3-1)*cos(10*x)*(0*x+10*1)*2-((sin(10*x))^3*(2)'))/(2^2)
(3*(sin(10*x))^(3-1)*10*cos(10*x)*2-((sin(10*x))^3*(2)'))/(2^2)
(30*(sin(10*x))^2*cos(10*x)*2-((sin(10*x))^3*(2)'))/(2^2)
(30*(sin(10*x))^2*cos(10*x)*2-((sin(10*x))^3*0))/(2^2)
15*(sin(10*x))^2*cos(10*x)
| Derivative of (3t-1)(6t-6)^-1 | | Derivative of (8e^x)/(7e^x-9) | | Derivative of 8e^x/7e^x-9 | | Derivative of Cos(4x^5) | | Derivative of -0.4sin(2x)cos(4t) | | Derivative of (x)sin(2X) | | Derivative of -0.4cos(4t)sin(2x) | | Derivative of 5x-3ln(x) | | Derivative of 5/3*x^(-1/3)*(x-2) | | Derivative of (4*sin(x/2)) | | Derivative of sin(4*e^t) | | Derivative of (Ln(13)) | | Derivative of Tan(4x)^2 | | Derivative of 2ln(x)^4 | | Derivative of 4/5x^-4/5 | | Derivative of 9sin(9x) | | Derivative of ln((x)(e^(-2x))) | | Derivative of (3*2^(2*x)) | | Derivative of (7)/(ln(x)) | | Derivative of Sin(5(ln(x))) | | Derivative of (6x)(ln(3x))-6x | | Derivative of pi/((5x)^2) | | Derivative of Ln(2*pi*x^2) | | Derivative of (tan(x))^5x | | Derivative of 128/2x | | Derivative of e^0.04x | | Derivative of 6e^-5x | | Derivative of 11e^c | | Derivative of sin(x^3-x) | | Derivative of x^(-e) | | Derivative of 2-cos(3x) | | Derivative of 5e^1-x^2 |