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((2*x^2+3*x)*(x+1)^0.5)'The calculation above is a derivative of the function f (x)

(2*x^2+3*x)'*(x+1)^0.5+(2*x^2+3*x)*((x+1)^0.5)'

((2*x^2)'+(3*x)')*(x+1)^0.5+(2*x^2+3*x)*((x+1)^0.5)'

(2*(x^2)'+(3*x)'+(2)'*x^2)*(x+1)^0.5+(2*x^2+3*x)*((x+1)^0.5)'

(2*(x^2)'+(3*x)'+0*x^2)*(x+1)^0.5+(2*x^2+3*x)*((x+1)^0.5)'

((3*x)'+2*2*x^(2-1)+0*x^2)*(x+1)^0.5+(2*x^2+3*x)*((x+1)^0.5)'

((3*x)'+2*2*x+0*x^2)*(x+1)^0.5+(2*x^2+3*x)*((x+1)^0.5)'

(3*(x)'+4*x+(3)'*x)*(x+1)^0.5+(2*x^2+3*x)*((x+1)^0.5)'

(3*(x)'+4*x+0*x)*(x+1)^0.5+(2*x^2+3*x)*((x+1)^0.5)'

(4*x+0*x+3*1)*(x+1)^0.5+(2*x^2+3*x)*((x+1)^0.5)'

(4*x+3)*(x+1)^0.5+(2*x^2+3*x)*((x+1)^0.5)'

(4*x+3)*(x+1)^0.5+(2*x^2+3*x)*0.5*(x+1)^(0.5-1)*(x+1)'

(4*x+3)*(x+1)^0.5+(2*x^2+3*x)*0.5*(x+1)^(0.5-1)*((x)'+(1)')

(4*x+3)*(x+1)^0.5+(2*x^2+3*x)*0.5*(x+1)^(0.5-1)*((1)'+1)

(4*x+3)*(x+1)^0.5+(2*x^2+3*x)*0.5*(x+1)^(0.5-1)*(0+1)

(4*x+3)*(x+1)^0.5+(2*x^2+3*x)*0.5*(x+1)^(0.5-1)*1

(4*x+3)*(x+1)^0.5+(2*x^2+3*x)*0.5*(x+1)^-0.5

(4*x+3)*(x+1)^0.5+0.5*(2*x^2+3*x)*(x+1)^-0.5

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