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(((x+1)^1)/2)'The calculation above is a derivative of the function f (x)

(((x+1)^1)'*2-((x+1)^1*(2)'))/(2^2)

(1*(x+1)^(1-1)*(x+1)'*2-((x+1)^1*(2)'))/(2^2)

(1*(x+1)^(1-1)*((x)'+(1)')*2-((x+1)^1*(2)'))/(2^2)

(1*(x+1)^(1-1)*((1)'+1)*2-((x+1)^1*(2)'))/(2^2)

(1*(x+1)^(1-1)*(0+1)*2-((x+1)^1*(2)'))/(2^2)

(1*(x+1)^(1-1)*1*2-((x+1)^1*(2)'))/(2^2)

(1*2-((x+1)^1*(2)'))/(2^2)

(1*2-((x+1)^1*0))/(2^2)

1/2

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