d=5/2(m-32)

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Solution for d=5/2(m-32) equation: 


x in (-oo:+oo)

d = (5/2)*(m-32) // - (5/2)*(m-32)

d-((5/2)*(m-32)) = 0

(-5/2)*(m-32)+d = 0

d-5/2*(m-32) = 0

d-5/2*(m-32) = 0

d-5/2*m+80 = 0

d-5/2*m+80 = 0

x belongs to the empty set

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