d=12-(1+4d)

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Solution for d=12-(1+4d) equation: 



d=12-(1+4d)

We move all terms to the left:

d-(12-(1+4d))=0

We add all the numbers together, and all the variables

d-(12-(4d+1))=0



We calculate terms in parentheses: -(12-(4d+1)), so:

12-(4d+1)

determiningTheFunctionDomain
-(4d+1)+12

We get rid of parentheses

-4d-1+12

We add all the numbers together, and all the variables

-4d+11

Back to the equation:

-(-4d+11)



We get rid of parentheses

d+4d-11=0

We add all the numbers together, and all the variables

5d-11=0

We move all terms containing d to the left, all other terms to the right

5d=11

d=11/5

d=2+1/5

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