d=(b-c)/a

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Solution for d=(b-c)/a equation: 


x in (-oo:+oo)

d = (b-c)/a // - (b-c)/a

d-((b-c)/a) = 0

(-1*(b-c))/a+d = 0

(-1*(b-c))/a+(a*d)/a = 0

a*d-1*(b-c) = 0

c-b+a*d = 0

(c-b+a*d)/a = 0

(c-b+a*d)/a = 0 // * a

c-b+a*d = 0

x belongs to the empty set

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