d+(2d+1)+4d+(4d+8)+3/4*4d=121

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Solution for d+(2d+1)+4d+(4d+8)+3/4*4d=121 equation:



d+(2d+1)+4d+(4d+8)+3/4*4d=121
We move all terms to the left:
d+(2d+1)+4d+(4d+8)+3/4*4d-(121)=0
Domain of the equation: 4*4d!=0
d!=0/1
d!=0
d∈R
We add all the numbers together, and all the variables
5d+(2d+1)+(4d+8)+3/4*4d-121=0
We get rid of parentheses
5d+2d+4d+3/4*4d+1+8-121=0
We multiply all the terms by the denominator
5d*4*4d+2d*4*4d+4d*4*4d+1*4*4d+8*4*4d-121*4*4d+3=0
Wy multiply elements
80d^2*4+32d^2*4+64d^2*4+16d*4+128d*4-1936d*4+3=0
Wy multiply elements
320d^2+128d^2+256d^2+64d+512d-7744d+3=0
We add all the numbers together, and all the variables
704d^2-7168d+3=0
a = 704; b = -7168; c = +3;
Δ = b2-4ac
Δ = -71682-4·704·3
Δ = 51371776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{51371776}=\sqrt{256*200671}=\sqrt{256}*\sqrt{200671}=16\sqrt{200671}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7168)-16\sqrt{200671}}{2*704}=\frac{7168-16\sqrt{200671}}{1408} $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7168)+16\sqrt{200671}}{2*704}=\frac{7168+16\sqrt{200671}}{1408} $

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