d(d-3)-40=0

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Solution for d(d-3)-40=0 equation:


Simplifying
d(d + -3) + -40 = 0

Reorder the terms:
d(-3 + d) + -40 = 0
(-3 * d + d * d) + -40 = 0
(-3d + d2) + -40 = 0

Reorder the terms:
-40 + -3d + d2 = 0

Solving
-40 + -3d + d2 = 0

Solving for variable 'd'.

Factor a trinomial.
(-5 + -1d)(8 + -1d) = 0

Subproblem 1

Set the factor '(-5 + -1d)' equal to zero and attempt to solve: Simplifying -5 + -1d = 0 Solving -5 + -1d = 0 Move all terms containing d to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1d = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1d = 0 + 5 -1d = 0 + 5 Combine like terms: 0 + 5 = 5 -1d = 5 Divide each side by '-1'. d = -5 Simplifying d = -5

Subproblem 2

Set the factor '(8 + -1d)' equal to zero and attempt to solve: Simplifying 8 + -1d = 0 Solving 8 + -1d = 0 Move all terms containing d to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1d = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1d = 0 + -8 -1d = 0 + -8 Combine like terms: 0 + -8 = -8 -1d = -8 Divide each side by '-1'. d = 8 Simplifying d = 8

Solution

d = {-5, 8}

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