cos(x)+cos(2x)-cos(3x)-1=0

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Solution for cos(x)+cos(2x)-cos(3x)-1=0 equation:


Simplifying
cos(x) + cos(2x) + -1cos(3x) + -1 = 0

Multiply cos * x
cosx + cos(2x) + -1cos(3x) + -1 = 0

Remove parenthesis around (2x)
cosx + cos * 2x + -1cos(3x) + -1 = 0

Reorder the terms for easier multiplication:
cosx + 2cos * x + -1cos(3x) + -1 = 0

Multiply cos * x
cosx + 2cosx + -1cos(3x) + -1 = 0

Remove parenthesis around (3x)
cosx + 2cosx + -1cos * 3x + -1 = 0

Reorder the terms for easier multiplication:
cosx + 2cosx + -1 * 3cos * x + -1 = 0

Multiply -1 * 3
cosx + 2cosx + -3cos * x + -1 = 0

Multiply cos * x
cosx + 2cosx + -3cosx + -1 = 0

Reorder the terms:
-1 + cosx + 2cosx + -3cosx = 0

Combine like terms: cosx + 2cosx = 3cosx
-1 + 3cosx + -3cosx = 0

Combine like terms: 3cosx + -3cosx = 0
-1 + 0 = 0
-1 = 0

Solving
-1 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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