cos(x)+cos(2x)+cos(3x)+cos(4x)=0

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Solution for cos(x)+cos(2x)+cos(3x)+cos(4x)=0 equation:


Simplifying
cos(x) + cos(2x) + cos(3x) + cos(4x) = 0

Multiply cos * x
cosx + cos(2x) + cos(3x) + cos(4x) = 0

Remove parenthesis around (2x)
cosx + cos * 2x + cos(3x) + cos(4x) = 0

Reorder the terms for easier multiplication:
cosx + 2cos * x + cos(3x) + cos(4x) = 0

Multiply cos * x
cosx + 2cosx + cos(3x) + cos(4x) = 0

Remove parenthesis around (3x)
cosx + 2cosx + cos * 3x + cos(4x) = 0

Reorder the terms for easier multiplication:
cosx + 2cosx + 3cos * x + cos(4x) = 0

Multiply cos * x
cosx + 2cosx + 3cosx + cos(4x) = 0

Remove parenthesis around (4x)
cosx + 2cosx + 3cosx + cos * 4x = 0

Reorder the terms for easier multiplication:
cosx + 2cosx + 3cosx + 4cos * x = 0

Multiply cos * x
cosx + 2cosx + 3cosx + 4cosx = 0

Combine like terms: cosx + 2cosx = 3cosx
3cosx + 3cosx + 4cosx = 0

Combine like terms: 3cosx + 3cosx = 6cosx
6cosx + 4cosx = 0

Combine like terms: 6cosx + 4cosx = 10cosx
10cosx = 0

Solving
10cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '10'.
cosx = 0.0

Simplifying
cosx = 0.0

The solution to this equation could not be determined.

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