cos(3x)-cos(x)=-2sin(2x)sin(x)

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Solution for cos(3x)-cos(x)=-2sin(2x)sin(x) equation:


Simplifying
cos(3x) + -1cos(x) = -2sin(2x) * sin(x)

Remove parenthesis around (3x)
cos * 3x + -1cos(x) = -2sin(2x) * sin(x)

Reorder the terms for easier multiplication:
3cos * x + -1cos(x) = -2sin(2x) * sin(x)

Multiply cos * x
3cosx + -1cos(x) = -2sin(2x) * sin(x)

Multiply cos * x
3cosx + -1cosx = -2sin(2x) * sin(x)

Combine like terms: 3cosx + -1cosx = 2cosx
2cosx = -2sin(2x) * sin(x)

Remove parenthesis around (2x)
2cosx = -2ins * 2x * sin(x)

Reorder the terms for easier multiplication:
2cosx = -2 * 2ins * x * ins * x

Multiply -2 * 2
2cosx = -4ins * x * ins * x

Multiply ins * x
2cosx = -4insx * ins * x

Multiply insx * ins
2cosx = -4i2n2s2x * x

Multiply i2n2s2x * x
2cosx = -4i2n2s2x2

Solving
2cosx = -4i2n2s2x2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '2osx'.
c = -2i2n2o-1sx

Simplifying
c = -2i2n2o-1sx

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