cos(2x)sin(x)+sin(x)=0

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Solution for cos(2x)sin(x)+sin(x)=0 equation:


Simplifying
cos(2x) * sin(x) + sin(x) = 0

Remove parenthesis around (2x)
cos * 2x * sin(x) + sin(x) = 0

Reorder the terms for easier multiplication:
2cos * x * ins * x + sin(x) = 0

Multiply cos * x
2cosx * ins * x + sin(x) = 0

Multiply cosx * ins
2cinos2x * x + sin(x) = 0

Multiply cinos2x * x
2cinos2x2 + sin(x) = 0

Multiply ins * x
2cinos2x2 + insx = 0

Solving
2cinos2x2 + insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1insx' to each side of the equation.
2cinos2x2 + insx + -1insx = 0 + -1insx

Combine like terms: insx + -1insx = 0
2cinos2x2 + 0 = 0 + -1insx
2cinos2x2 = 0 + -1insx
Remove the zero:
2cinos2x2 = -1insx

Divide each side by '2inos2x2'.
c = -0.5o-1s-1x-1

Simplifying
c = -0.5o-1s-1x-1

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