cos(2x)+cos(4x)-cos(3x)=0

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Solution for cos(2x)+cos(4x)-cos(3x)=0 equation:


Simplifying
cos(2x) + cos(4x) + -1cos(3x) = 0

Remove parenthesis around (2x)
cos * 2x + cos(4x) + -1cos(3x) = 0

Reorder the terms for easier multiplication:
2cos * x + cos(4x) + -1cos(3x) = 0

Multiply cos * x
2cosx + cos(4x) + -1cos(3x) = 0

Remove parenthesis around (4x)
2cosx + cos * 4x + -1cos(3x) = 0

Reorder the terms for easier multiplication:
2cosx + 4cos * x + -1cos(3x) = 0

Multiply cos * x
2cosx + 4cosx + -1cos(3x) = 0

Remove parenthesis around (3x)
2cosx + 4cosx + -1cos * 3x = 0

Reorder the terms for easier multiplication:
2cosx + 4cosx + -1 * 3cos * x = 0

Multiply -1 * 3
2cosx + 4cosx + -3cos * x = 0

Multiply cos * x
2cosx + 4cosx + -3cosx = 0

Combine like terms: 2cosx + 4cosx = 6cosx
6cosx + -3cosx = 0

Combine like terms: 6cosx + -3cosx = 3cosx
3cosx = 0

Solving
3cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '3'.
cosx = 0

Simplifying
cosx = 0

The solution to this equation could not be determined.

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