cos^2(3x)+sin^2(3x)=1

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Solution for cos^2(3x)+sin^2(3x)=1 equation: 


Simplifying
cos2(3x) + sin2(3x) = 1

Remove parenthesis around (3x)
cos2 * 3x + sin2(3x) = 1

Reorder the terms for easier multiplication:
3cos2 * x + sin2(3x) = 1

Multiply cos2 * x
3cos2x + sin2(3x) = 1

Remove parenthesis around (3x)
3cos2x + in2s * 3x = 1

Reorder the terms for easier multiplication:
3cos2x + 3in2s * x = 1

Multiply in2s * x
3cos2x + 3in2sx = 1

Solving
3cos2x + 3in2sx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3in2sx' to each side of the equation.
3cos2x + 3in2sx + -3in2sx = 1 + -3in2sx

Combine like terms: 3in2sx + -3in2sx = 0
3cos2x + 0 = 1 + -3in2sx
3cos2x = 1 + -3in2sx

Divide each side by '3os2x'.
c = 0.3333333333o-1s-2x-1 + -1in2o-1s-1

Simplifying
c = 0.3333333333o-1s-2x-1 + -1in2o-1s-1

Reorder the terms:
c = -1in2o-1s-1 + 0.3333333333o-1s-2x-1

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