c2+11c=6

Solution for c2+11c=6 equation:

c2+11c=6

We move all terms to the left:

c2+11c-(6)=0

We add all the numbers together, and all the variables

c^2+11c-6=0

a = 1; b = 11; c = -6;
Δ = b2-4ac
Δ = 112-4·1·(-6)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{145}}{2*1}=\frac{-11-\sqrt{145}}{2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{145}}{2*1}=\frac{-11+\sqrt{145}}{2}
$