c/4c-8=16-2c

Solution for c/4c-8=16-2c equation:

c/4c-8=16-2c

We move all terms to the left:

c/4c-8-(16-2c)=0


Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R


We add all the numbers together, and all the variables

c/4c-(-2c+16)-8=0

We get rid of parentheses

c/4c+2c-16-8=0

We multiply all the terms by the denominator


c+2c*4c-16*4c-8*4c=0

Wy multiply elements

8c^2+c-64c-32c=0

We add all the numbers together, and all the variables

8c^2-95c=0

a = 8; b = -95; c = 0;
Δ = b2-4ac
Δ = -952-4·8·0
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-95}{2*8}=\frac{0}{16}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+95}{2*8}=\frac{190}{16}
=11+7/8
$