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c-3=2(1-c)-2
We move all terms to the left:
c-3-(2(1-c)-2)=0
We add all the numbers together, and all the variables
c-(2(-1c+1)-2)-3=0
We calculate terms in parentheses: -(2(-1c+1)-2), so:We get rid of parentheses
2(-1c+1)-2
We multiply parentheses
-2c+2-2
We add all the numbers together, and all the variables
-2c
Back to the equation:
-(-2c)
c+2c-3=0
We add all the numbers together, and all the variables
3c-3=0
We move all terms containing c to the left, all other terms to the right
3c=3
c=3/3
c=1
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