c-2(a+b)+3(a-b)=

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Solution for c-2(a+b)+3(a-b)= equation:


Simplifying
c + -2(a + b) + 3(a + -1b) = 0
c + (a * -2 + b * -2) + 3(a + -1b) = 0
c + (-2a + -2b) + 3(a + -1b) = 0
c + -2a + -2b + (a * 3 + -1b * 3) = 0
c + -2a + -2b + (3a + -3b) = 0

Reorder the terms:
-2a + 3a + -2b + -3b + c = 0

Combine like terms: -2a + 3a = 1a
1a + -2b + -3b + c = 0

Combine like terms: -2b + -3b = -5b
1a + -5b + c = 0

Solving
1a + -5b + c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5b' to each side of the equation.
1a + -5b + 5b + c = 0 + 5b

Combine like terms: -5b + 5b = 0
1a + 0 + c = 0 + 5b
1a + c = 0 + 5b
Remove the zero:
1a + c = 5b

Add '-1c' to each side of the equation.
1a + c + -1c = 5b + -1c

Combine like terms: c + -1c = 0
1a + 0 = 5b + -1c
1a = 5b + -1c

Divide each side by '1'.
a = 5b + -1c

Simplifying
a = 5b + -1c

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