c+5=4/9c

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Solution for c+5=4/9c equation:



c+5=4/9c
We move all terms to the left:
c+5-(4/9c)=0
Domain of the equation: 9c)!=0
c!=0/1
c!=0
c∈R
We add all the numbers together, and all the variables
c-(+4/9c)+5=0
We get rid of parentheses
c-4/9c+5=0
We multiply all the terms by the denominator
c*9c+5*9c-4=0
Wy multiply elements
9c^2+45c-4=0
a = 9; b = 45; c = -4;
Δ = b2-4ac
Δ = 452-4·9·(-4)
Δ = 2169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2169}=\sqrt{9*241}=\sqrt{9}*\sqrt{241}=3\sqrt{241}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-3\sqrt{241}}{2*9}=\frac{-45-3\sqrt{241}}{18} $
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+3\sqrt{241}}{2*9}=\frac{-45+3\sqrt{241}}{18} $

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