c+2c-3c+4c=16

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Solution for c+2c-3c+4c=16 equation: 



c+2c-3c+4c=16

We move all terms to the left:

c+2c-3c+4c-(16)=0

We add all the numbers together, and all the variables

4c-16=0

We move all terms containing c to the left, all other terms to the right

4c=16

c=16/4

c=4

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