c+2c+4c-5=23

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Solution for c+2c+4c-5=23 equation: 



c+2c+4c-5=23

We move all terms to the left:

c+2c+4c-5-(23)=0

We add all the numbers together, and all the variables

7c-28=0

We move all terms containing c to the left, all other terms to the right

7c=28

c=28/7

c=4

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