c(c-3)=40

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Solution for c(c-3)=40 equation:


Simplifying
c(c + -3) = 40

Reorder the terms:
c(-3 + c) = 40
(-3 * c + c * c) = 40
(-3c + c2) = 40

Solving
-3c + c2 = 40

Solving for variable 'c'.

Reorder the terms:
-40 + -3c + c2 = 40 + -40

Combine like terms: 40 + -40 = 0
-40 + -3c + c2 = 0

Factor a trinomial.
(-5 + -1c)(8 + -1c) = 0

Subproblem 1

Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5

Subproblem 2

Set the factor '(8 + -1c)' equal to zero and attempt to solve: Simplifying 8 + -1c = 0 Solving 8 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1c = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1c = 0 + -8 -1c = 0 + -8 Combine like terms: 0 + -8 = -8 -1c = -8 Divide each side by '-1'. c = 8 Simplifying c = 8

Solution

c = {-5, 8}

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