c(2c+4)+2(7-c*c)=40

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Solution for c(2c+4)+2(7-c*c)=40 equation: 


Simplifying
c(2c + 4) + 2(7 + -1c * c) = 40

Reorder the terms:
c(4 + 2c) + 2(7 + -1c * c) = 40
(4 * c + 2c * c) + 2(7 + -1c * c) = 40
(4c + 2c2) + 2(7 + -1c * c) = 40

Multiply c * c
4c + 2c2 + 2(7 + -1c2) = 40
4c + 2c2 + (7 * 2 + -1c2 * 2) = 40
4c + 2c2 + (14 + -2c2) = 40

Reorder the terms:
14 + 4c + 2c2 + -2c2 = 40

Combine like terms: 2c2 + -2c2 = 0
14 + 4c + 0 = 40
14 + 4c = 40

Solving
14 + 4c = 40

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 4c = 40 + -14

Combine like terms: 14 + -14 = 0
0 + 4c = 40 + -14
4c = 40 + -14

Combine like terms: 40 + -14 = 26
4c = 26

Divide each side by '4'.
c = 6.5

Simplifying
c = 6.5

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