b=3/2(j-37)

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Solution for b=3/2(j-37) equation: 


x in (-oo:+oo)

b = (3/2)*(j-37) // - (3/2)*(j-37)

b-((3/2)*(j-37)) = 0

(-3/2)*(j-37)+b = 0

b-3/2*(j-37) = 0

b-3/2*(j-37) = 0

b-3/2*j+111/2 = 0

b-3/2*j+111/2 = 0

x belongs to the empty set

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