b2=12/116

Solution for b2=12/116 equation:

b2=12/116

We move all terms to the left:

b2-(12/116)=0

We add all the numbers together, and all the variables

b2-(+12/116)=0

We add all the numbers together, and all the variables

b^2-(+12/116)=0

We get rid of parentheses

b^2-12/116=0

We multiply all the terms by the denominator


b^2*116-12=0

Wy multiply elements

116b^2-12=0

a = 116; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·116·(-12)
Δ = 5568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5568}=\sqrt{64*87}=\sqrt{64}*\sqrt{87}=8\sqrt{87}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{87}}{2*116}=\frac{0-8\sqrt{87}}{232}
=-\frac{8\sqrt{87}}{232}
=-\frac{\sqrt{87}}{29}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{87}}{2*116}=\frac{0+8\sqrt{87}}{232}
=\frac{8\sqrt{87}}{232}
=\frac{\sqrt{87}}{29}
$