b2+8b=-16

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Solution for b2+8b=-16 equation: 



b2+8b=-16

We move all terms to the left:

b2+8b-(-16)=0

We add all the numbers together, and all the variables

b^2+8b+16=0

a = 1; b = 8; c = +16;
Δ = b2-4ac
Δ = 82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{-8}{2}=-4$

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