b/4=(b-8)/5

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Solution for b/4=(b-8)/5 equation: 



b/4=(b-8)/5

We move all terms to the left:

b/4-((b-8)/5)=0

We calculate fractions


5b^2/()+(-((b-8)*4)/()=0



We calculate terms in parentheses: +(-((b-8)*4)/(), so:

-((b-8)*4)/(

We multiply all the terms by the denominator


-((b-8)*4)



We calculate terms in parentheses: -((b-8)*4), so:

(b-8)*4

We multiply parentheses

4b-32

Back to the equation:

-(4b-32)



We get rid of parentheses

-4b+32

Back to the equation:

+(-4b+32)



We get rid of parentheses

5b^2/()-4b+32=0

We multiply all the terms by the denominator


5b^2-4b*()+32*()=0

We add all the numbers together, and all the variables

5b^2-4b*()=0

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