b/4-6=3b/4-+19

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Solution for b/4-6=3b/4-+19 equation: 



b/4-6=3b/4-+19

We move all terms to the left:

b/4-6-(3b/4-+19)=0

We add all the numbers together, and all the variables

b/4-(+3b/4)-6=0

We get rid of parentheses

b/4-3b/4-6=0

We multiply all the terms by the denominator


b-3b-6*4=0

We add all the numbers together, and all the variables

-2b-24=0

We move all terms containing b to the left, all other terms to the right

-2b=24

b=24/-2

b=-12

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