b/3b+4=29-2b

Solution for b/3b+4=29-2b equation:

b/3b+4=29-2b

We move all terms to the left:

b/3b+4-(29-2b)=0


Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R


We add all the numbers together, and all the variables

b/3b-(-2b+29)+4=0

We get rid of parentheses

b/3b+2b-29+4=0

We multiply all the terms by the denominator


b+2b*3b-29*3b+4*3b=0

Wy multiply elements

6b^2+b-87b+12b=0

We add all the numbers together, and all the variables

6b^2-74b=0

a = 6; b = -74; c = 0;
Δ = b2-4ac
Δ = -742-4·6·0
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-74)-74}{2*6}=\frac{0}{12}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-74)+74}{2*6}=\frac{148}{12}
=12+1/3
$