b.2/3b+5=20-b

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Solution for b.2/3b+5=20-b equation: 



b.2/3b+5=20-b

We move all terms to the left:

b.2/3b+5-(20-b)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

b.2/3b-(-1b+20)+5=0

We get rid of parentheses

b.2/3b+1b-20+5=0

We multiply all the terms by the denominator


b.2+1b*3b-20*3b+5*3b=0

Wy multiply elements

3b^2+b.2-60b+15b=0

We add all the numbers together, and all the variables

3b^2-45b+b.2=0

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